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Rewrite the function by completing the square.

{:[f(x)=x^(2)+20 x-86],[f(x)=(x+◻)^(2)+◻]:}

Rewrite the function by completing the square.\newlinef(x)=x2+20x86 f(x) = x^2 + 20x - 86 \newlinef(x)=(x+)2+ f(x) = (x + \square)^2 + \square

Full solution

Q. Rewrite the function by completing the square.\newlinef(x)=x2+20x86 f(x) = x^2 + 20x - 86 \newlinef(x)=(x+)2+ f(x) = (x + \square)^2 + \square
  1. Given quadratic function: We start with the given quadratic function:\newlinef(x) = x^22 + 2020x - 8686\newlineTo complete the square, we need to form a perfect square trinomial from the x^22 and x terms. We will find the value to add and subtract to complete the square.
  2. Completing the square: The coefficient of x is 2020. To complete the square, we take half of the coefficient of x, square it, and add it to and subtract it from the equation. This value is (202)2=102=100(\frac{20}{2})^2 = 10^2 = 100.
  3. Adding and subtracting 100100: We add and subtract 100100 inside the function:\newlinef(x) = (x2+20x+100)10086(x^2 + 20x + 100) - 100 - 86\newlineNow we have a perfect square trinomial x2+20x+100x^2 + 20x + 100, which can be factored into (x+10)2(x + 10)^2.
  4. Factoring the perfect square trinomial: We simplify the constants 100-100 and 86-86:\newlinef(x) = (x + 1010)^22 - 100100 - 8686\newlinef(x) = (x + 1010)^22 - 186186\newlineNow the function is written in the completed square form.

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