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Rewrite the function by completing the square. {:[f(x)=x^(2)-16 x+76],[f(x)=(x+◻)^(2)+◻]:}

Rewrite the function by completing the square.\newlinef(x)=x2−16x+76 f(x) = x^2 - 16x + 76 \newlinef(x)=(x+□)2+□ f(x) = (x + \square)^2 + \square

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Q. Rewrite the function by completing the square.\newlinef(x)=x2−16x+76 f(x) = x^2 - 16x + 76 \newlinef(x)=(x+□)2+□ f(x) = (x + \square)^2 + \square
  1. Rewriting the function: Now we rewrite the function by factoring the perfect square trinomial and combining the constants.\newlinef(x)=(x−8)2+76−64f(x) = (x - 8)^2 + 76 - 64\newlinef(x)=(x−8)2+12f(x) = (x - 8)^2 + 12
  2. Completing the square: We have successfully rewritten the function by completing the square. The function is now in the form f(x)=(x−h)2+kf(x) = (x - h)^2 + k, where hh and kk are constants.\newlineThe completed square form of the function is f(x)=(x−8)2+12f(x) = (x - 8)^2 + 12.

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