Paulo's economics course requires two papers-one long and one short-throughout the semester. The number of pages, l, in the long paper is 1 more than 2 times the number of pages, s, in the short paper. If the total number of pages for both papers is 40 , how many pages must be in the long paper?

Question

Paulo's economics course requires two papers-one long and one short-throughout the semester. The number of pages,  l, in the long paper is 1 more than 2 times the number of pages,  s, in the short paper. If the total number of pages for both papers is 40 , how many pages must be in the long paper?

Bytelearn · Accepted Answer

Set up equation: Set up the equation based on the given information. We know that the long paper has 1 more page than twice the number of pages in the short paper. This can be written as: l = 2s + 1 We also know that the total number of pages for both papers is 40, which gives us another equation: l + s = 40Substitute and simplify: Substitute the expression for l from the first equation into the second equation. Using l = 2s + 1, we substitute l in the second equation to get: (2s + 1) + s = 40Solve for s: Simplify the equation and solve for s. Combining like terms, we get: 3s + 1 = 40 Now, subtract 1 from both sides to isolate the terms with s: 3s = 40 - 1 3s = 39 Next, divide both sides by 3 to solve for s: s = 39 / 3 s = 13Find number of pages: Determine the number of pages in the long paper using the value of s. Now that we know s = 13, we can use the first equation to find l: l = 2s + 1 l = 2(13) + 1 l = 26 + 1 l = 27

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