Olivia has a 20 -meter-long fence that she plans to use to enclose a rectangular garden of width w. The fencing will be placed around all four sides of the garden so that its area is 18.75 square meters.Write an equation in terms of w that models the situation.
Q. Olivia has a 20 -meter-long fence that she plans to use to enclose a rectangular garden of width w. The fencing will be placed around all four sides of the garden so that its area is 18.75 square meters.Write an equation in terms of w that models the situation.
Perimeter equation: Let's denote the width of the garden as w meters and the length as l meters. The perimeter of the garden is the sum of all four sides, which is given as 20 meters. The perimeter P of a rectangle is given by P=2l+2w. Since we know the total perimeter is 20 meters, we can write the equation:2l+2w=20
Simplifying the equation: We can simplify this equation by dividing everything by 2 to make it easier to solve for one of the variables:l+w=10Now we have an equation relating the length and width of the garden.
Area equation: We also know the area A of the garden is given by A=l×w. The problem states that the area is 18.75 square meters, so we can write the equation:l×w=18.75
Expressing l in terms of w: We can use the perimeter equation to express l in terms of w. From the simplified perimeter equation l+w=10, we can solve for l:l=10−w
Equation in terms of w: Now we can substitute the expression for l into the area equation to write an equation only in terms of w:(10−w)⋅w=18.75This is the equation that models the situation in terms of w.
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