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Mustafa is staring at a pizza spinning on a wheel in a glass case.
The pizza is cut into four even slices. The distance 
P(t) (in 
cm ) between the center of the tastiest looking slice and the door of the glass case as a function of time 
t (in seconds) can be modeled by a sinusoidal function of the form 
a*cos(b*t)+d.
At 
t=0, the center of the tastiest looking slice is farthest from the door, at a distance of 
30cm away. After 
2pi seconds, it is closest to the door, at a distance of 
10cm.
Find 
P(t).

t should be in radians.

P(t)=◻

Mustafa is staring at a pizza spinning on a wheel in a glass case.\newlineThe pizza is cut into four even slices. The distance P(t) P(t) (in cm \mathrm{cm} ) between the center of the tastiest looking slice and the door of the glass case as a function of time t t (in seconds) can be modeled by a sinusoidal function of the form acos(bt)+d a \cdot \cos (b \cdot t)+d .\newlineAt t=0 t=0 , the center of the tastiest looking slice is farthest from the door, at a distance of 30 cm 30 \mathrm{~cm} away. After 2π 2 \pi seconds, it is closest to the door, at a distance of 10 cm 10 \mathrm{~cm} .\newlineFind P(t) P(t) .\newlinet t should be in radians.\newlineP(t)= P(t)=

Full solution

Q. Mustafa is staring at a pizza spinning on a wheel in a glass case.\newlineThe pizza is cut into four even slices. The distance P(t) P(t) (in cm \mathrm{cm} ) between the center of the tastiest looking slice and the door of the glass case as a function of time t t (in seconds) can be modeled by a sinusoidal function of the form acos(bt)+d a \cdot \cos (b \cdot t)+d .\newlineAt t=0 t=0 , the center of the tastiest looking slice is farthest from the door, at a distance of 30 cm 30 \mathrm{~cm} away. After 2π 2 \pi seconds, it is closest to the door, at a distance of 10 cm 10 \mathrm{~cm} .\newlineFind P(t) P(t) .\newlinet t should be in radians.\newlineP(t)= P(t)=
  1. Given Information: We are given that the distance P(t)P(t) is modeled by a sinusoidal function of the form acos(bt)+da\cos(bt)+d. At t=0t=0, the distance is the maximum, which is 30cm30\,\text{cm}. This means that the value of dd plus aa must equal 30cm30\,\text{cm}, since the cosine function has its maximum value of 11 at t=0t=0.
  2. Maximum Distance: We also know that after 2π2\pi seconds, the distance is at its minimum, which is 10cm10\,\text{cm}. This means that the value of dad - a must equal 10cm10\,\text{cm}, since the cosine function has its minimum value of 1-1 at t=2πt=2\pi for the first time.
  3. Minimum Distance: From the two conditions, we can set up a system of equations:\newline11. a+d=30a + d = 30\newline22. da=10d - a = 10\newlineAdding these two equations, we get 2d=402d = 40, which means d=20cmd = 20\,\text{cm}.
  4. System of Equations: Subtracting the second equation from the first, we get 2a=202a = 20, which means a=10cma = 10\,\text{cm}.
  5. Solving for d: Now we need to determine the value of b. Since the pizza completes one full cycle from the farthest point to the closest point and back to the farthest point in 22\pi seconds, the period of the function is 44\pi seconds. The period T of a cosine function is given by T = \frac{22\pi}{b}, so we have 44\pi = \frac{22\pi}{b}.
  6. Solving for aa: Solving for bb, we get b=2π4π=12b = \frac{2\pi}{4\pi} = \frac{1}{2}.
  7. Determining the Value of b: Now we have all the parameters for the sinusoidal function: a=10a = 10 cm, b=12b = \frac{1}{2}, and d=20d = 20 cm. The function P(t)P(t) is therefore P(t)=10cos(12t)+20P(t) = 10\cos\left(\frac{1}{2}t\right) + 20.

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