Multiply and simplify the following complex numbers: (-3+3i)*(3-2i) +=^(-x)

Apply distributive property: Apply the distributive property to multiply the two complex numbers. (-3+3i)*(3-2i) = (-3 * 3) + (-3 * -2i) + (3i * 3) + (3i * -2i)Calculate multiplications: Calculate each multiplication separately. (-3 * 3) = -9 (-3 * -2i) = 6i (3i * 3) = 9i (3i * -2i) = -6i^2Combine like terms: Combine like terms and remember that i^2 = -1. -9 + 6i + 9i - 6(-1)Simplify expression: Simplify the expression by adding real parts and imaginary parts separately and substituting i^2 with -1. -9 + 6i + 9i + 6Combine real and imaginary parts: Combine the real numbers and the imaginary numbers. (-9 + 6) + (6i + 9i)Finish simplification: Finish the simplification. -3 + 15i

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Multiply and simplify the following complex numbers:

(-3+3i)*(3-2i)

+=^(-x)

Multiply and simplify the following complex numbers: $\newline$ $(-3+3 i) \cdot(3-2 i)$ $\newline$ $+\stackrel{-}{=}$

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Math Problems

Algebra 1

Simplify linear expressions using properties

Full solution

Q. Multiply and simplify the following complex numbers:

\newline

(-3+3 i) \cdot(3-2 i)

\newline

+\stackrel{-}{=}

Apply distributive property: Apply the distributive property to multiply the two complex numbers. $\newline$ $(-3+3i)*(3-2i) = (-3 \times 3) + (-3 \times -2i) + (3i \times 3) + (3i \times -2i)$
Calculate multiplications: Calculate each multiplication separately. $\newline$ $(-3 \times 3) = -9$ $\newline$ $(-3 \times -2i) = 6i$ $\newline$ $(3i \times 3) = 9i$ $\newline$ $(3i \times -2i) = -6i^2$
Combine like terms: Combine like terms and remember that $i^2 = -1$ . $\newline$ $-9 + 6i + 9i - 6(-1)$
Simplify expression: Simplify the expression by adding real parts and imaginary parts separately and substituting $i^2$ with $-1$ . $\newline$ $-9 + 6i + 9i + 6$
Combine real and imaginary parts: Combine the real numbers and the imaginary numbers. $(-9 + 6) + (6i + 9i)$
Finish simplification: Finish the simplification. $\newline$ $-3 + 15i$