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Ling needs to fit a pane of glass in an opening with a maximum diagonal length of 62 inches. The glass has a diagonal length of 61.98 inches at room temperature. For every increase of 1 degree Celsius (^(@)C), the pane of glass will expand 0.00056 inch diagonally. Which of the following is closest to the maximum temperature increase from room temperature the pane of glass can experience and still fit in the opening? Choose 1 answer: (A) 1^(@)C (B) 4^(@)C (C) 10^(@)C (D) 36^(@)C

Ling needs to fit a pane of glass in an opening with a maximum diagonal length of 6262 inches. The glass has a diagonal length of 6161.9898 inches at room temperature. For every increase of 11 degree Celsius (∘C) \left({ }^{\circ} \mathrm{C}\right) , the pane of glass will expand 00.0005600056 inch diagonally. Which of the following is closest to the maximum temperature increase from room temperature the pane of glass can experience and still fit in the opening?\newlineChoose 11 answer:\newline(A) 1∘C 1^{\circ} \mathrm{C} \newline(B) 4∘C 4^{\circ} \mathrm{C} \newline(C) 10∘C 10^{\circ} \mathrm{C} \newline(D) 36∘C 36^{\circ} \mathrm{C}

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Q. Ling needs to fit a pane of glass in an opening with a maximum diagonal length of 6262 inches. The glass has a diagonal length of 6161.9898 inches at room temperature. For every increase of 11 degree Celsius (∘C) \left({ }^{\circ} \mathrm{C}\right) , the pane of glass will expand 00.0005600056 inch diagonally. Which of the following is closest to the maximum temperature increase from room temperature the pane of glass can experience and still fit in the opening?\newlineChoose 11 answer:\newline(A) 1∘C 1^{\circ} \mathrm{C} \newline(B) 4∘C 4^{\circ} \mathrm{C} \newline(C) 10∘C 10^{\circ} \mathrm{C} \newline(D) 36∘C 36^{\circ} \mathrm{C}
  1. Determine Maximum Expansion: Determine the maximum allowable expansion of the glass pane. The maximum diagonal length the opening can accommodate is 6262 inches, and the glass pane is currently 61.9861.98 inches at room temperature. Therefore, the maximum expansion allowed is the difference between these two lengths. Maximum expansion = 6262 inches - 61.9861.98 inches = 0.020.02 inches.
  2. Calculate Temperature Increase: Calculate the temperature increase that corresponds to the maximum expansion.\newlineWe know that for every 11 degree Celsius increase in temperature, the glass expands by 0.000560.00056 inch diagonally. To find the temperature increase that would cause an expansion of 0.020.02 inches, we divide the maximum expansion by the expansion rate per degree Celsius.\newlineTemperature increase =Maximum expansionExpansion per degree Celsius= \frac{\text{Maximum expansion}}{\text{Expansion per degree Celsius}}\newlineTemperature increase =0.02 inches0.00056 inch/degree Celsius= \frac{0.02 \text{ inches}}{0.00056 \text{ inch/degree Celsius}}\newlineTemperature increase ≈35.7142857\approx 35.7142857 degrees Celsius
  3. Round Temperature Increase: Round the temperature increase to the nearest whole number and select the closest answer choice.\newlineSince we are looking for the closest maximum temperature increase, we round the calculated temperature increase to the nearest whole number.\newlineRounded temperature increase ≈36∘C\approx 36^\circ \text{C}

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