Keala is making a new book cover before giving their favorite picture book to their little brother. The cover is 22(1)/(4)cm tall. It has a rectangular shape and an area of 890cm^(2). How wide across is Keala's book cover? cm

Question

Keala is making a new book cover before giving their favorite picture book to their little brother. The cover is  22(1)/(4)cm tall. It has a rectangular shape and an area of  890cm^(2). How wide across is Keala's book cover? cm

Bytelearn · Accepted Answer

Identify Known Values: : Step 1: Identify the known values from the problem. Keala's book cover is 22(1/4) cm tall and has an area of 890 cm². Convert to Improper Fraction: : Step 2: Convert the mixed number for the height into an improper fraction. 22(1/4) cm can be converted to an improper fraction by multiplying the whole number 22 by the denominator 4 and adding the numerator 1. 22 * 4 + 1 = 88 + 1 = 89 So, 22(1/4) cm is 89/4 cm. Write Area Formula: : Step 3: Write down the formula for the area of a rectangle. The area (A) of a rectangle is given by the formula A = length (l) * width (w). Set Up Equation: : Step 4: Set up the equation to solve for the width. We know the area (A) is 890 cm² and the length (l), which is the height of the book cover, is 89/4 cm. We need to find the width (w). So, 890 = (89/4) * w Solve for Width: : Step 5: Solve for the width (w). To find w, divide both sides of the equation by (89/4). w = 890 / (89/4) w = 890 * (4/89) Perform Division: : Step 6: Perform the division to find the width. w = 890 * (4/89) w = (890/89) * 4 w = 10 * 4 w = 40 So, the width of Keala's book cover is 40 cm.

Keala is making a new book cover before giving their favorite picture book to their little brother. The cover is $22 \frac{1}{4} \mathrm{~cm}$ tall. It has a rectangular shape and an area of $890 \mathrm{~cm}^{2}$ . $\newline$ How wide across is Keala's book cover? $\newline$ cm

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