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Jacob's classroom contains tables and chairs, each with 4 legs. Jacob puts a pad on the end of every leg so that the tables and chairs will not make noise when they are moved around. If Jacob needs exactly 80 pads for his classroom, which of the following equations correctly relates the number of chairs, 
c, to the number of tables, 
t ?
Choose 1 answer:
(A) 
c=80-4t
(B) 
c=80-t
(C) 
c=20-4t
(D) 
c=20-t

Jacob's classroom contains tables and chairs, each with 44 legs. Jacob puts a pad on the end of every leg so that the tables and chairs will not make noise when they are moved around. If Jacob needs exactly 8080 pads for his classroom, which of the following equations correctly relates the number of chairs, c c , to the number of tables, t t ?\newlineChoose 11 answer:\newline(A) c=804t c=80-4 t \newline(B) c=80t c=80-t \newline(C) c=204t c=20-4 t \newline(D) c=20t c=20-t

Full solution

Q. Jacob's classroom contains tables and chairs, each with 44 legs. Jacob puts a pad on the end of every leg so that the tables and chairs will not make noise when they are moved around. If Jacob needs exactly 8080 pads for his classroom, which of the following equations correctly relates the number of chairs, c c , to the number of tables, t t ?\newlineChoose 11 answer:\newline(A) c=804t c=80-4 t \newline(B) c=80t c=80-t \newline(C) c=204t c=20-4 t \newline(D) c=20t c=20-t
  1. Identify variables and constants: Identify the variables and constants in the problem.\newlineEach chair has 44 legs, so each chair will need 44 pads.\newlineEach table also has 44 legs, so each table will need 44 pads.\newlineThe total number of pads needed is 8080.\newlineLet cc represent the number of chairs and tt represent the number of tables.
  2. Set up equation: Set up the equation based on the information given.\newlineThe total number of pads is the sum of the pads needed for all the chairs and all the tables.\newlineSo, the equation is 4c4c (pads for chairs) + 4t4t (pads for tables) = 8080 (total pads).
  3. Simplify equation: Simplify the equation to relate cc and tt.\newlineDivide the entire equation by 44 to simplify it:\newline4c4+4t4=804\frac{4c}{4} + \frac{4t}{4} = \frac{80}{4}\newlineThis simplifies to:\newlinec+t=20c + t = 20
  4. Rearrange to solve: Rearrange the equation to solve for cc in terms of tt.\newlineSubtract tt from both sides of the equation:\newlinec+tt=20tc + t - t = 20 - t\newlineThis simplifies to:\newlinec=20tc = 20 - t

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