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In the
xy-plane, the graph of
f(x)=2x^(2)-6x-8 is a parabola. What is the
y-intercept of the parabola?
Choose 1 answer:
(A) -8
(B) -6
(c) -4
(D) -2

In the $x y$ -plane, the graph of $f(x)=2 x^{2}-6 x-8$ is a parabola. What is the $y$ -intercept of the parabola? $\newline$ Choose $1$ answer: $\newline$ (A) $-8$ $\newline$ (B) $-6$ $\newline$ (C) $-4$ $\newline$ (D) $-2$

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Characteristics of quadratic functions: equations

Full solution

Q. In the

x y

-plane, the graph of

f(x)=2 x^{2}-6 x-8

is a parabola. What is the

y

-intercept of the parabola?

\newline

Choose

1

answer:

\newline

(A)

-8

\newline

(B)

-6

\newline

(C)

-4

\newline

(D)

-2

Step $1$ : Find y-intercept: To find the y-intercept of the parabola, we need to evaluate the function $f(x)$ when $x = 0$ . The y-intercept is the point where the graph of the function crosses the y-axis, which occurs at $x = 0$ .
Step $2$ : Substitute $x = 0$ : Substitute $x = 0$ into the function $f(x) = 2x^2 - 6x - 8$ . $\newline$ $f(0) = 2(0)^2 - 6(0) - 8$ $\newline$ $f(0) = 0 - 0 - 8$ $\newline$ $f(0) = -8$
Step $3$ : Calculate $f(0)$ : The $y$ -intercept of the parabola is the point $(0, f(0))$ , which is $(0, -8)$ . Therefore, the correct answer is (A) $-8$ .

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