Q. If (x,y) is a solution to the system of equations shown, what is the product of the y-coordinates of the solutions?x2+y2=9x+y=3
Given Equations: We are given the system of equations:1. x2+y2=92. x+y=3We need to find the y-coordinates of the solutions to these equations and then calculate their product. Let's start by expressing x in terms of y using the second equation.x=3−y
Expressing x in terms of y: Now, we substitute x=3−y into the first equation to find y.(3−y)2+y2=9Expanding the squared term, we get:9−6y+y2+y2=9Simplifying, we combine like terms:2y2−6y=0
Substituting x into the first equation: We can factor out a y from the equation:y(2y−6)=0This gives us two possible solutions for y:1. y=02. 2y−6=0 which simplifies to y=3
Factoring out y: We have two y-coordinates for the solutions: y=0 and y=3. To find the product of the y-coordinates, we multiply these two values together:Product of y-coordinates = y1×y2=0×3=0
Finding the y-coordinates: The product of the y-coordinates of the solutions to the system of equations is 0.
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