Q. If f(x)=3x−1 and g(x)=x2+1, what is the value of g(f(3)) ?Choose 1 answer:(A) 8(B) 10(C) 29(D) 65
Find f(3): Given the functions f(x)=3x−1 and g(x)=x2+1, we first need to find the value of f(3). f(x)=3x−1 f(3)=3(3)−1 f(3)=9−1 f(3)=8
Substitute f(3) into g(x): Now that we have f(3)=8, we need to find the value of g(f(3)), which means we need to substitute x in g(x) with the value of f(3). g(x)=x2+1 g(f(3))=g(8)=82+1 g(f(3))=64+1 g(f(3))=65
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