If (1)/(5)h+25=d, which of the following expressions is equivalent to h ? Choose 1 answer: (A) (1)/(5)d-5 (B) (1)/(5)d+25 (c) 5d-125 (D) 5d-25

Isolate h in equation: We have the equation: (1/5)h + 25 = d To solve for h, we need to isolate h on one side of the equation.Subtract 25: Subtract 25 from both sides of the equation to move the constant term to the other side: (1/5)h + 25 - 25 = d - 25Simplify equation: Simplify both sides of the equation: (1/5)h = d - 25Multiply by 5: Multiply both sides of the equation by 5 to solve for h: 5 * (1/5)h = 5 * (d - 25)Final solution: Simplify the multiplication: h = 5d - 125

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If
(1)/(5)h+25=d, which of the following expressions is equivalent to
h ?
Choose 1 answer:
(A)
(1)/(5)d-5
(B)
(1)/(5)d+25
(c)
5d-125
(D)
5d-25

If $\frac{1}{5} h+25=d$ , which of the following expressions is equivalent to $h$ ? $\newline$ Choose $1$ answer: $\newline$ (A) $\frac{1}{5} d-5$ $\newline$ (B) $\frac{1}{5} d+25$ $\newline$ (C) $5 d-125$ $\newline$ (D) $5 d-25$

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Math Problems

Algebra 1

Identify equivalent linear expressions

Full solution

Q. If

\frac{1}{5} h+25=d

, which of the following expressions is equivalent to

h

\newline

Choose

1

answer:

\newline

(A)

\frac{1}{5} d-5

\newline

(B)

\frac{1}{5} d+25

\newline

(C)

5 d-125

\newline

(D)

5 d-25

Isolate $h$ in equation: We have the equation: $\newline$ $\frac{1}{5}h + 25 = d$ $\newline$ To solve for $h$ , we need to isolate $h$ on one side of the equation.
Subtract $25$ : Subtract $25$ from both sides of the equation to move the constant term to the other side: $\newline$ $\frac{1}{5}h + 25 - 25 = d - 25$
Simplify equation: Simplify both sides of the equation: $\newline$ $\frac{1}{5}h = d - 25$
Multiply by $5$ : Multiply both sides of the equation by $5$ to solve for $h$ : $5 \times \left(\frac{1}{5}\right)h = 5 \times (d - 25)$
Final solution: Simplify the multiplication: $\newline$ $h = 5d - 125$