For t!=0, which of the following expressions is equivalent to (-12t^(2)-18 t)/(8t^(2)+18 t)" ? " Choose 1 answer: (A) (6t+9)/(4t+9) (B) (-6t+9)/(4t+9) (c) (-6t-1)/(4t+1) (D) (-6t-9)/(4t+9)

Factor out common terms: Factor out the common terms in the numerator and the denominator. The numerator has a common factor of -6t, and the denominator has a common factor of 2t. (-12t^2 - 18t) = -6t(2t + 3) (8t^2 + 18t) = 2t(4t + 9)Simplify by canceling common t terms: Simplify the expression by canceling out the common t terms, since t is not equal to 0. The expression becomes: (-6t(2t + 3))/(2t(4t + 9)) = (-6(2t + 3))/(2(4t + 9))Further simplify by canceling common factor: Simplify the expression further by canceling out the common factor of 2. The expression becomes: (-3(2t + 3))/(4t + 9) = (-6t - 9)/(4t + 9)

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For
t!=0, which of the following expressions is equivalent to

(-12t^(2)-18 t)/(8t^(2)+18 t)" ? "
Choose 1 answer:
(A)
(6t+9)/(4t+9)
(B)
(-6t+9)/(4t+9)
(c)
(-6t-1)/(4t+1)
(D)
(-6t-9)/(4t+9)

For $t \neq 0$ , which of the following expressions is equivalent to $\frac{-12 t^{2}-18 t}{8 t^{2}+18 t}$ ? $\newline$ Choose $1$ answer: $\newline$ (A) $\frac{6 t+9}{4 t+9}$ $\newline$ (B) $\frac{-6 t+9}{4 t+9}$ $\newline$ (C) $\frac{-6 t-1}{4 t+1}$ $\newline$ (D) $\frac{-6 t-9}{4 t+9}$

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Math Problems

Grade 7

Identify equivalent linear expressions I

Full solution

Q. For

t \neq 0

, which of the following expressions is equivalent to

\frac{-12 t^{2}-18 t}{8 t^{2}+18 t}

\newline

Choose

1

answer:

\newline

(A)

\frac{6 t+9}{4 t+9}

\newline

(B)

\frac{-6 t+9}{4 t+9}

\newline

(C)

\frac{-6 t-1}{4 t+1}

\newline

(D)

\frac{-6 t-9}{4 t+9}

Factor out common terms: Factor out the common terms in the numerator and the denominator. $\newline$ The numerator has a common factor of $-6t$ , and the denominator has a common factor of $2t$ . $\newline$ $(-12t^2 - 18t) = -6t(2t + 3)$ $\newline$ $(8t^2 + 18t) = 2t(4t + 9)$
Simplify by canceling common t terms: Simplify the expression by canceling out the common t terms, since $t \neq 0$ . $\newline$ The expression becomes: $\newline$ $\frac{-6t(2t + 3)}{2t(4t + 9)}$ $\newline$ $= \frac{-6(2t + 3)}{2(4t + 9)}$
Further simplify by canceling common factor: Simplify the expression further by canceling out the common factor of $2$ . $\newline$ The expression becomes: $\newline$ $\frac{-3(2t + 3)}{4t + 9}$ $\newline$ $= \frac{-6t - 9}{4t + 9}$