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Find an explicit formula for the arithmetic sequence 
-2,-14,-26,-38,dots.. Note: the first term should be 
d(1).

d(n)=

Find an explicit formula for the arithmetic sequence\newline2,14,26,38,..  -2,-14,-26,-38, \ldots \text {.. } \newlineNote: the first term should be d(1) d(1) .\newlined(n)= d(n)=

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Q. Find an explicit formula for the arithmetic sequence\newline2,14,26,38,..  -2,-14,-26,-38, \ldots \text {.. } \newlineNote: the first term should be d(1) d(1) .\newlined(n)= d(n)=
  1. Identify the sequence type and pattern: Identify the type of sequence and the pattern. The sequence -2 ext{,} -14 ext{,} -26 ext{,} -38 ext{,} \ ext{...} ext{)} decreases by the same amount each time, which indicates it is an arithmetic sequence. The common difference \$d can be found by subtracting any term from the term that follows it.\newlineCalculation: d=14(2)=14+2=12d = -14 - (-2) = -14 + 2 = -12
  2. Calculate the common difference: Use the explicit formula for an arithmetic sequence, which is d(n)=d(1)+(n1)dd(n) = d(1) + (n-1)d, where d(1)d(1) is the first term and dd is the common difference.\newlineIn this sequence, the first term d(1)d(1) is 2-2 and the common difference dd is 12-12.
  3. Use the explicit formula for arithmetic sequence: Substitute the values of d(1)d(1) and dd into the formula to find the explicit formula for the sequence.\newlineCalculation: d(n)=2+(n1)(12)d(n) = -2 + (n-1)(-12)
  4. Substitute values into the formula: Simplify the expression to get the final explicit formula for the sequence.\newlineCalculation: d(n)=212(n1)=212n+12=12n+10d(n) = -2 - 12(n-1) = -2 - 12n + 12 = -12n + 10

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