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Factor completely.

x^(3)+7x^(2)-5x-35=

Factor completely.\newlinex3+7x25x35= x^{3}+7 x^{2}-5 x-35=

Full solution

Q. Factor completely.\newlinex3+7x25x35= x^{3}+7 x^{2}-5 x-35=
  1. Identify Common Factors: Look for common factors in all terms. Check if there is a greatest common factor (GCF) that can be factored out from all terms of the polynomial x3+7x25x35x^3 + 7x^2 - 5x - 35. Since there are no common factors in all terms, we cannot factor out a GCF.
  2. Group Terms for Factoring: Group terms to factor by grouping.\newlineSince the polynomial has four terms, we can try to factor by grouping. Group the first two terms together and the last two terms together: (x3+7x2)+(5x35)(x^3 + 7x^2) + (-5x - 35).
  3. Factor Out Common Factors: Factor out the common factor from each group.\newlineFrom the first group x3+7x2x^3 + 7x^2, we can factor out x2x^2, which gives us x2(x+7)x^2(x + 7).\newlineFrom the second group 5x35-5x - 35, we can factor out 5-5, which gives us 5(x+7)-5(x + 7).\newlineNow we have x2(x+7)5(x+7)x^2(x + 7) - 5(x + 7).
  4. Factor Out Common Binomial: Factor out the common binomial factor.\newlineWe can see that (x+7)(x + 7) is a common factor in both terms. Factor out (x+7)(x + 7) from the expression.\newlineThis gives us (x+7)(x25)(x + 7)(x^2 - 5).
  5. Check Quadratic Factorability: Check if the remaining quadratic can be factored further.\newlineThe quadratic x25x^2 - 5 does not factor over the integers because it does not have integer roots. Therefore, it is already in its simplest form.