Factor completely. 64y^(6)-48y^(3)+9=

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Factor completely.  64y^(6)-48y^(3)+9=

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Identify Structure of Expression: Step Title: Identify the Structure of the Expression Concise Step Description: Recognize that the expression is a trinomial that may be a perfect square trinomial or factorable using the difference of squares. Step Calculation: The expression is 64y^(6) - 48y^(3) + 9. Step Output: The expression is a trinomial.Check for Perfect Square Trinomial: Step Title: Check for a Perfect Square Trinomial Concise Step Description: Determine if the first and last terms are perfect squares and if the middle term is twice the product of the square roots of the first and last terms. Step Calculation: The first term, 64y^(6), is a perfect square (8y^(3))^2. The last term, 9, is a perfect square (3)^2. The middle term, -48y^(3), is twice the product of 8y^(3) and 3, which is -2 * 8y^(3) * 3 = -48y^(3). Step Output: The expression is a perfect square trinomial.Write Factored Form: Step Title: Write the Factored Form of the Perfect Square Trinomial Concise Step Description: Express the trinomial as the square of a binomial. Step Calculation: The factored form is (8y^(3) - 3)^2. Step Output: Factored Form: (8y^(3) - 3)^2

Factor completely. $\newline$ $64 y^{6}-48 y^{3}+9=$

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Factor completely.\newline64y6−48y3+9= 64 y^{6}-48 y^{3}+9= 64y6−48y3+9=

Factor completely. $\newline$ $64 y^{6}-48 y^{3}+9=$