Factor completely. 128-32 x+2x^(2)=

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Factor completely.  128-32 x+2x^(2)=

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Recognize and Determine Factoring Strategy: Recognize the type of polynomial and determine the factoring strategy. The given polynomial is a quadratic in the form of ax^2 + bx + c. We can attempt to factor it by finding two numbers that multiply to ac (the product of the coefficient of x^2 and the constant term) and add up to b (the coefficient of x).Identify Coefficients: Identify the coefficients a, b, and c in the quadratic expression 2x^2 - 32x + 128. a = 2, b = -32, c = 128Find Multiplying and Adding Numbers: Find two numbers that multiply to ac (2 * 128 = 256) and add up to b (-32). The two numbers that satisfy these conditions are -16 and -16, since (-16) * (-16) = 256 and (-16) + (-16) = -32.Rewrite Middle Term: Rewrite the middle term -32x using the two numbers found in Step 3. 2x^2 - 32x + 128 = 2x^2 - 16x - 16x + 128Factor by Grouping: Factor by grouping. Group the terms into two pairs: (2x^2 - 16x) and (-16x + 128). Factor out the greatest common factor from each pair. 2x(x - 8) - 16(x - 8)Factor out Common Binomial Factor: Factor out the common binomial factor (x - 8). (2x - 16)(x - 8)Further Factor 2x - 16: Recognize that 2x - 16 can be further factored by taking out the common factor of 2. 2(x - 8)(x - 8)Write Final Factored Form: Write the final factored form. The factored form of the expression is 2(x - 8)^2.

Factor completely. $\newline$ $128-32x+2x^{2}=$

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Factor completely.\newline128−32x+2x2=128-32x+2x^{2}=128−32x+2x2=

Factor completely. $\newline$ $128-32x+2x^{2}=$