Factor as the product of two binomials. x^(2)-9x+20=

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Factor as the product of two binomials.  x^(2)-9x+20=

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Identify quadratic trinomial: Identify the quadratic trinomial and its structure. The given expression is x^2 - 9x + 20, which is in the standard form of a quadratic trinomial ax^2 + bx + c, where a = 1, b = -9, and c = 20.Determine factors of constant term: Determine the factors of the constant term c that add up to the coefficient b. We need to find two numbers that multiply to 20 (the constant term) and add up to -9 (the coefficient of x). The numbers that satisfy these conditions are -4 and -5, because (-4) * (-5) = 20 and (-4) + (-5) = -9.Rewrite middle term: Rewrite the middle term using the numbers found in Step 2. We can express -9x as the sum of -4x and -5x. Therefore, x^2 - 9x + 20 can be rewritten as x^2 - 4x - 5x + 20.Factor by grouping: Factor by grouping. We group the terms as follows: (x^2 - 4x) + (-5x + 20). Now we factor out the common factors from each group. From the first group, we can factor out an x, and from the second group, we can factor out a -5. This gives us x(x - 4) - 5(x - 4).Factor out common binomial factor: Factor out the common binomial factor. We notice that (x - 4) is a common factor in both terms. We can factor this out to get (x - 4)(x - 5) as the final factored form of the expression.

Factor as the product of two binomials. $\newline$ $x^{2}-9x+20=$

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Factor as the product of two binomials.\newlinex2−9x+20=x^{2}-9x+20=x2−9x+20=

Factor as the product of two binomials. $\newline$ $x^{2}-9x+20=$