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Factor as the product of two binomials.

x^(2)+6x+9=

Factor as the product of two binomials.\newlinex2+6x+9=x^{2}+6x+9=

Full solution

Q. Factor as the product of two binomials.\newlinex2+6x+9=x^{2}+6x+9=
  1. Check for Perfect Square Trinomial: Determine if the quadratic can be factored as a perfect square trinomial.\newlineA perfect square trinomial is in the form (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2. We need to check if x2+6x+9x^2 + 6x + 9 fits this pattern.
  2. Identify Square Roots: Identify the square root of the first term and the last term.\newlineThe square root of x2x^2 is xx, and the square root of 99 is 33. So, we have a=xa = x and b=3b = 3.
  3. Verify Middle Term: Check if the middle term fits the pattern 2ab2ab.\newlineFor our expression, the middle term is 6x6x. We need to see if this equals 2×x×32 \times x \times 3.\newline2×x×3=6x2 \times x \times 3 = 6x, which matches the middle term of our expression.
  4. Write as Square of Binomial: Write the expression as the square of a binomial.\newlineSince the expression fits the pattern of a perfect square trinomial, we can write it as (x+3)2(x + 3)^2.