Factor as the product of two binomials. x^(2)-64=◻++x__

Determine the approach: Determine the approach to factor x^2 - 64. We can recognize x^2 - 64 as a difference of squares since both x^2 and 64 are perfect squares. Difference of squares formula: a^2 - b^2 = (a - b)(a + b).Identify the form: Identify x^2 - 64 in the form of a^2 - b^2. x^2 = x * x = (x)^2 64 = 8 * 8 = 8^2 So, x^2 - 64 = (x)^2 - 8^2Apply the difference of squares formula: Apply the difference of squares formula to factor the expression. (x)^2 - 8^2 = (x - 8)(x + 8) The factored form of x^2 - 64 is (x - 8)(x + 8).

Home

Math Problems

Algebra 1

Factor quadratics: special cases

Full solution

Q. Factor as the product of two binomials.

\newline

x^{2}-64=

Determine the approach: Determine the approach to factor $x^2 - 64$ . $\newline$ We can recognize $x^2 - 64$ as a difference of squares since both $x^2$ and $64$ are perfect squares. $\newline$ Difference of squares formula: $a^2 - b^2 = (a - b)(a + b)$ .
Identify the form: Identify $x^2 - 64$ in the form of $a^2 - b^2$ . $\newline$ $x^2 = x \times x = (x)^2$ $\newline$ $64 = 8 \times 8 = 8^2$ $\newline$ So, $x^2 - 64 = (x)^2 - 8^2$
Apply the difference of squares formula: Apply the difference of squares formula to factor the expression. $\newline$ $(x)^2 - 8^2 = (x - 8)(x + 8)$ $\newline$ The factored form of $x^2 - 64$ is $(x - 8)(x + 8)$ .