Factor as the product of two binomials. x^(2)-3x-10=

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Factor as the product of two binomials.  x^(2)-3x-10=

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Identify quadratic trinomial: Identify the quadratic trinomial and its structure. The given expression is x^2 - 3x - 10, which is in the standard form of a quadratic trinomial ax^2 + bx + c, where a = 1, b = -3, and c = -10.Determine factors of constant term: Determine the factors of the constant term c that add up to the coefficient b. We need to find two numbers that multiply to -10 (the constant term) and add up to -3 (the coefficient of x). The numbers that satisfy these conditions are -5 and +2.Rewrite middle term: Rewrite the middle term using the numbers found in Step 2. We can express -3x as -5x + 2x, which are the terms that come from the factors found in Step 2. So, x^2 - 3x - 10 becomes x^2 - 5x + 2x - 10.Factor by grouping: Factor by grouping. Group the terms into two pairs: (x^2 - 5x) and (2x - 10). Factor out the greatest common factor from each pair. From the first pair, we can factor out an x, giving us x(x - 5). From the second pair, we can factor out a 2, giving us 2(x - 5). Now we have x(x - 5) + 2(x - 5).Factor out common binomial factor: Factor out the common binomial factor. The common binomial factor is (x - 5). Factor this out to get (x - 5)(x + 2) as the product of two binomials.

Factor as the product of two binomials. $\newline$ $x^{2}-3x-10=$

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Factor as the product of two binomials.\newlinex2−3x−10=x^{2}-3x-10=x2−3x−10=

Factor as the product of two binomials. $\newline$ $x^{2}-3x-10=$