Factor as the product of two binomials. x^(2)+11 x+18=

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Factor as the product of two binomials.  x^(2)+11 x+18=

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Given Quadratic Expression: We are given the quadratic expression x^2 + 11x + 18 and need to factor it into the product of two binomials. The general form of a quadratic expression is ax^2 + bx + c, where a, b, and c are constants. In this case, a = 1, b = 11, and c = 18. We are looking for two numbers that multiply to ac (which is 18) and add up to b (which is 11).Finding the Factors: Let's list the pairs of factors of 18 (since ac = 18): (1, 18), (2, 9), (3, 6). We need to find a pair that adds up to 11 (since b = 11).Identifying the Numbers: Checking the pairs, we see that 2 and 9 add up to 11. Therefore, the two numbers we are looking for are 2 and 9.Writing as Product of Binomials: Now we can write the original quadratic expression as the product of two binomials using the numbers 2 and 9: (x + 2)(x + 9).Verifying the Factoring: To verify that we have factored correctly, we can use the FOIL method (First, Outer, Inner, Last) to expand the binomials and check if we get the original expression: First: x * x = x^2 Outer: x * 9 = 9x Inner: 2 * x = 2x Last: 2 * 9 = 18 Adding these together, we get x^2 + 9x + 2x + 18, which simplifies to x^2 + 11x + 18.

Factor as the product of two binomials. $\newline$ $x^{2}+11 x+18=$

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Factor as the product of two binomials.\newlinex2+11x+18= x^{2}+11 x+18= x2+11x+18=

Factor as the product of two binomials. $\newline$ $x^{2}+11 x+18=$