Factor as the product of two binomials. x^(2)-10 x+21=

Identify the form: Identify the form of the quadratic trinomial. x^2 - 10x + 21 represents the form ax^2 + bx + c, where a = 1, b = -10, and c = 21.Determine the factors: Determine the factors of the constant term, c, that add up to the coefficient of the x term, b. We need two numbers that multiply to 21 and add up to -10. The numbers that satisfy these conditions are -3 and -7, because (-3) * (-7) = 21 and (-3) + (-7) = -10.Write the factored form: Write the factored form of the expression x^2 - 10x + 21 using the numbers found in the previous step. The factored form will be (x - 3)(x - 7), because when we apply the distributive property (FOIL), we get x^2 - 7x - 3x + 21, which simplifies to x^2 - 10x + 21.

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Q. Factor as the product of two binomials.

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x^{2}-10x+21=

Identify the form: Identify the form of the quadratic trinomial. $x^2 - 10x + 21$ represents the form $ax^2 + bx + c$ , where $a = 1$ , $b = -10$ , and $c = 21$ .
Determine the factors: Determine the factors of the constant term, $c$ , that add up to the coefficient of the $x$ term, $b$ . $\newline$ We need two numbers that multiply to $21$ and add up to $-10$ . The numbers that satisfy these conditions are $-3$ and $-7$ , because $(-3) \times (-7) = 21$ and $(-3) + (-7) = -10$ .
Write the factored form: Write the factored form of the expression $x^2 - 10x + 21$ using the numbers found in the previous step. $\newline$ The factored form will be $(x - 3)(x - 7)$ , because when we apply the distributive property (FOIL), we get $x^2 - 7x - 3x + 21$ , which simplifies to $x^2 - 10x + 21$ .