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Factor as the product of two binomials.

49-14 x+x^(2)=

Factor as the product of two binomials.\newline4914x+x2=49-14x+x^{2}=

Full solution

Q. Factor as the product of two binomials.\newline4914x+x2=49-14x+x^{2}=
  1. Recognize the quadratic expression: Recognize the structure of the quadratic expression.\newlineThe given expression is in the form of a quadratic trinomial, which can often be factored into the product of two binomials.\newlineThe expression is 4914x+x249 - 14x + x^2.\newlineWe can reorder the terms to match the standard form of a quadratic equation, which is ax2+bx+cax^2 + bx + c.\newlineSo, the expression becomes x214x+49x^2 - 14x + 49.
  2. Reorder the terms: Look for a pattern that matches the square of a binomial.\newlineThe square of a binomial has the form (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2.\newlineWe can try to express x214x+49x^2 - 14x + 49 in this form.\newlineHere, a2=x2a^2 = x^2, so a=xa = x.\newlineWe need to find bb such that b2=49b^2 = 49 and 2ab=14x2ab = 14x.
  3. Look for a pattern: Find the value of bb.\newlineSince b2=49b^2 = 49, bb could be either 77 or 7-7.\newlineHowever, since we have 14x-14x in the expression, we need to choose b=7b = 7 to get the middle term 14x-14x (because 2ab=2×x×7=14x2ab = 2 \times x \times 7 = 14x).\newlineSo, b=7b = 7.
  4. Find the value of b: Write the factored form using the square of a binomial pattern.\newlineNow that we have a = x and b = 77, we can write the expression as the square of a binomial:\newlinex^22 - 1414x + 4949 = (x - 77)^22.\newlineThis is the factored form of the expression as the product of two identical binomials.