Factor 10 h+30+50 j to identify the equivalent expressions. Choose 2 answers: A 5(2h+30+50 j) B 10(h+3+5j) c 2(5h+15+25 j) D 15(10 h+2+50 j)

Identify Common Factor: Identify the common factor in all terms. Looking at the terms 10h, 30, and 50j, we can see that the number 10 is a common factor.Factor Out Common Factor: Factor out the common factor from each term. We can factor out the number 10 from each term to get: 10(h + 3 + 5j)Check Answer Choices: Check the answer choices to see which ones match the factored expression. Comparing the factored expression 10(h + 3 + 5j) with the answer choices, we find that: A. 5(2h + 30 + 50j) is not correct because it does not have the common factor 10 factored out correctly. B. 10(h + 3 + 5j) is correct because it matches our factored expression. C. 2(5h + 15 + 25j) is not correct because it factors out 2 instead of 10. D. 15(10h + 2 + 50j) is not correct because it factors out 15, which is not a common factor of all terms.

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Factor
10 h+30+50 j to identify the equivalent expressions.
Choose 2 answers:
A
5(2h+30+50 j)
B
10(h+3+5j)
c
2(5h+15+25 j)
D
15(10 h+2+50 j)

Factor $10 h+30+50 j$ to identify the equivalent expressions. $\newline$ Choose $2$ answers: $\newline$ A $5(2 h+30+50 j)$ $\newline$ B $10(h+3+5 j)$ $\newline$ c $2(5 h+15+25 j)$ $\newline$ D $15(10 h+2+50 j)$

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Math Problems

Grade 6

Factor numerical expressions using the distributive property

Full solution

Q. Factor

10 h+30+50 j

to identify the equivalent expressions.

\newline

Choose

2

answers:

\newline

5(2 h+30+50 j)

\newline

10(h+3+5 j)

\newline

2(5 h+15+25 j)

\newline

15(10 h+2+50 j)

Identify Common Factor: Identify the common factor in all terms. $\newline$ Looking at the terms $10h$ , $30$ , and $50j$ , we can see that the number $10$ is a common factor.
Factor Out Common Factor: Factor out the common factor from each term. $\newline$ We can factor out the number $10$ from each term to get: $\newline$ $10(h + 3 + 5j)$
Check Answer Choices: Check the answer choices to see which ones match the factored expression. $\newline$ Comparing the factored expression $10(h + 3 + 5j)$ with the answer choices, we find that: $\newline$ A. $5(2h + 30 + 50j)$ is not correct because it does not have the common factor $10$ factored out correctly. $\newline$ B. $10(h + 3 + 5j)$ is correct because it matches our factored expression. $\newline$ C. $2(5h + 15 + 25j)$ is not correct because it factors out $2$ instead of $10$ . $\newline$ D. $15(10h + 2 + 50j)$ is not correct because it factors out $15$ , which is not a common factor of all terms.