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Evaluate (c)/(2)-3+(6)/(d) when c=14 and d=3.

Evaluate c2−3+6d\frac{c}{2}-3+\frac{6}{d} when c=14c=14 and d=3d=3.

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Full solution

Q. Evaluate c2−3+6d\frac{c}{2}-3+\frac{6}{d} when c=14c=14 and d=3d=3.
  1. Substitute values: Substitute the given values into the expression.\newline(c2)−3+(6d)(\frac{c}{2}) - 3 + (\frac{6}{d}) becomes (142)−3+(63)(\frac{14}{2}) - 3 + (\frac{6}{3})
  2. Simplify terms: Simplify each term.\newline(142)=7(\frac{14}{2}) = 7\newline(63)=2(\frac{6}{3}) = 2\newlineSo, 7−3+27 - 3 + 2
  3. Perform operations: Perform the addition and subtraction.\newline7−3=47 - 3 = 4\newline4+2=64 + 2 = 6

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