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Evaluate 
5c+cd when 
c=(1)/(5) and 
d=15.

Evaluate 5c+cd5c+cd when c=15c=\frac{1}{5} and d=15d=15.

Full solution

Q. Evaluate 5c+cd5c+cd when c=15c=\frac{1}{5} and d=15d=15.
  1. Substitute given values: Substitute the given values for cc and dd into the expression 5c+cd5c+cd.c=15c = \frac{1}{5} and d=15d = 15 Expression: 5(15)+(15)155\left(\frac{1}{5}\right) + \left(\frac{1}{5}\right)15
  2. Simplify first term: Simplify the first term 5×(15)5\times\left(\frac{1}{5}\right).\newlineMultiplying 55 by (15)\left(\frac{1}{5}\right) cancels out the 55 in the denominator.\newline5×(15)=15\times\left(\frac{1}{5}\right) = 1
  3. Simplify second term: Simplify the second term (15)×15(\frac{1}{5})\times 15.\newlineMultiplying (15)(\frac{1}{5}) by 1515 is the same as dividing 1515 by 55.\newline(15)×15=3(\frac{1}{5})\times 15 = 3
  4. Add simplified terms: Add the simplified terms together.\newline1+3=41 + 3 = 4

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