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Evaluate (3)/(2)y-3+(5)/(3)z when y=6 and z=3.

Evaluate 32y−3+53z\frac{3}{2}y-3+\frac{5}{3}z when y=6y=6 and z=3z=3.

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Full solution

Q. Evaluate 32y−3+53z\frac{3}{2}y-3+\frac{5}{3}z when y=6y=6 and z=3z=3.
  1. Substitute values: Substitute y=6y=6 and z=3z=3 into the expression.\newline(32)∗6−3+(53)∗3\left(\frac{3}{2}\right)*6 - 3 + \left(\frac{5}{3}\right)*3
  2. Simplify terms: Simplify each term.\newline(32)⋅6=9(\frac{3}{2})\cdot 6 = 9\newline(53)⋅3=5(\frac{5}{3})\cdot 3 = 5\newlineNow we have 9−3+59 - 3 + 5
  3. Perform addition and subtraction: Perform the addition and subtraction. 9−3+5=6+5=119 - 3 + 5 = 6 + 5 = 11

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