Evaluate. (2)/(5)÷(1)/(7)=

Understanding division of fractions: Understand the operation of division between two fractions. To divide one fraction by another, we multiply the first fraction by the reciprocal of the second fraction. The reciprocal of a fraction is obtained by swapping its numerator and denominator.Finding the reciprocal of a fraction: Find the reciprocal of the second fraction. The reciprocal of (1)/(7) is (7)/(1), because we swap the numerator and the denominator.Multiplying fractions: Multiply the first fraction by the reciprocal of the second fraction. (2)/(5) ÷ (1)/(7) becomes (2)/(5) * (7)/(1).Performing the multiplication: Perform the multiplication. Multiply the numerators together and the denominators together. (2 * 7) / (5 * 1) = 14 / 5.Simplifying the result: Simplify the result if necessary. In this case, 14/5 is already in its simplest form, so no further simplification is needed.

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Math Problems

Grade 7

Add, subtract, multiply, and divide integers

Full solution

Q. Evaluate.

\newline

\frac{2}{5} \div \frac{1}{7}=

Understanding division of fractions: Understand the operation of division between two fractions. $\newline$ To divide one fraction by another, we multiply the first fraction by the reciprocal of the second fraction. The reciprocal of a fraction is obtained by swapping its numerator and denominator.
Finding the reciprocal of a fraction: Find the reciprocal of the second fraction. $\newline$ The reciprocal of $(\frac{1}{7})$ is $(\frac{7}{1})$ , because we swap the numerator and the denominator.
Multiplying fractions: Multiply the first fraction by the reciprocal of the second fraction. $\newline$ $(\frac{2}{5}) \div (\frac{1}{7})$ becomes $(\frac{2}{5}) \times (\frac{7}{1})$ .
Performing the multiplication: Perform the multiplication. $\newline$ Multiply the numerators together and the denominators together. $\newline$ $(2 \times 7) / (5 \times 1) = 14 / 5$ .
Simplifying the result: Simplify the result if necessary. $\newline$ In this case, $\frac{14}{5}$ is already in its simplest form, so no further simplification is needed.