Divide the polynomials. Your answer should be in the form p(x)+(k)/(x) where p is a polynomial and k is an integer. (6x^(5)-2x^(4)-1)/(x)=

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Divide the polynomials. Your answer should be in the form  p(x)+(k)/(x) where  p is a polynomial and  k is an integer.  (6x^(5)-2x^(4)-1)/(x)=

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Divide first term: To divide a polynomial by a monomial, we divide each term of the polynomial by the monomial. We start with the first term of the polynomial $6x^5$. Dividing $6x^5$ by $x$ gives us $6x^4$.Divide second term: Next, we divide the second term of the polynomial $-2x^4$ by $x$. Dividing $-2x^4$ by $x$ gives us $-2x^3$.Divide constant term: The last term of the polynomial is a constant term $-1$, which does not contain the variable $x$. When we divide a constant by $x$, we cannot simplify it further, so it becomes the remainder of the division. Dividing $-1$ by $x$ gives us $-1/x$, which we write as the remainder.Combine divided terms: Combining all the terms we have divided, we get the polynomial part $p(x) = 6x^4 - 2x^3$ and the remainder $-1/x$. So, the division can be expressed as $p(x) + \frac{k}{x}$, where $p(x) = 6x^4 - 2x^3$ and $k = -1$.

Divide the polynomials. Your answer should be in the form $p(x)+\frac{k}{x}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{6 x^{5}-2 x^{4}-1}{x}=$

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Divide the polynomials. Your answer should be in the form p(x)+kx p(x)+\frac{k}{x} p(x)+xk​ where p p p is a polynomial and k k k is an integer.\newline6x5−2x4−1x= \frac{6 x^{5}-2 x^{4}-1}{x}= x6x5−2x4−1​=

Divide the polynomials. Your answer should be in the form $p(x)+\frac{k}{x}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{6 x^{5}-2 x^{4}-1}{x}=$