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Let’s check out your problem:
Distribute to create an equivalent expression with the fewest symbols possible.
\newline
1
5
(
15
+
10
k
)
=
□
\frac{1}{5}(15+10 k)=\square
5
1
(
15
+
10
k
)
=
□
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Math Problems
Algebra 1
Domain and range of relations
Full solution
Q.
Distribute to create an equivalent expression with the fewest symbols possible.
\newline
1
5
(
15
+
10
k
)
=
□
\frac{1}{5}(15+10 k)=\square
5
1
(
15
+
10
k
)
=
□
Distribute the fraction:
Distribute the
fraction
(
1
5
)
(\frac{1}{5})
(
5
1
)
to both terms inside the parentheses
(
15
+
10
k
)
(15 + 10k)
(
15
+
10
k
)
.
\newline
Calculation:
(
1
5
)
×
15
+
(
1
5
)
×
10
k
(\frac{1}{5}) \times 15 + (\frac{1}{5}) \times 10k
(
5
1
)
×
15
+
(
5
1
)
×
10
k
Simplify each term:
Simplify each term.
\newline
Calculation:
(
1
5
)
×
15
=
3
(\frac{1}{5}) \times 15 = 3
(
5
1
)
×
15
=
3
and
(
1
5
)
×
10
k
=
2
k
(\frac{1}{5}) \times 10k = 2k
(
5
1
)
×
10
k
=
2
k
Write the simplified expression:
Write the simplified expression.
\newline
Calculation:
3
+
2
k
3 + 2k
3
+
2
k
More problems from Domain and range of relations
Question
Look at this set of ordered pairs:
(
3
,
18
)
(
15
,
9
)
(
13
,
14
)
(
18
,
12
)
(3, 18) (15, 9) (13, 14) (18, 12)
(
3
,
18
)
(
15
,
9
)
(
13
,
14
)
(
18
,
12
)
Is this relation a function
?
?
?
Choices:
[
[
yes
]
[[\text{yes}]
[[
yes
]
[
no
]
]
[\text{no}]]
[
no
]]
Get tutor help
Posted 9 months ago
Question
Use the following function rule to find
g
(
b
+
2
)
g(b + 2)
g
(
b
+
2
)
.
\newline
Simplify your answer.
\newline
g
(
a
)
=
4
a
+
8
g(a) = 4a + 8
g
(
a
)
=
4
a
+
8
g
(
b
+
2
)
=
g(b + 2) =
g
(
b
+
2
)
=
______
Get tutor help
Posted 9 months ago
Question
Thanks to an online typing course, Audrey has become a much faster typist. The function
f
(
x
)
f(x)
f
(
x
)
gives how many words she can type in
x
x
x
seconds.
\newline
What does
f
(
45
)
=
68
f(45) = 68
f
(
45
)
=
68
tell you?
\newline
Choices:
\newline
(A)
Audrey can type
68
words in
45
seconds.
\text{Audrey can type \( 68 \) words in \( 45 \) seconds.}
Audrey can type 68 words in 45 seconds.
\newline
(B)
Audrey can type
45
words in
68
seconds.
\text{Audrey can type \( 45 \) words in \( 68 \) seconds.}
Audrey can type 45 words in 68 seconds.
Get tutor help
Posted 9 months ago
Question
What is the domain of this relation?
\newline
(
4
,
−
3
)
(
−
3
,
−
10
)
(
−
5
,
5
)
(
9
,
−
2
)
(
9
,
−
1
)
(4,-3) (-3,-10) (-5,5) (9,-2) (9,-1)
(
4
,
−
3
)
(
−
3
,
−
10
)
(
−
5
,
5
)
(
9
,
−
2
)
(
9
,
−
1
)
\newline
Choices:
\newline
(A)
{
−
5
,
−
3
,
4
,
9
}
\{-5,-3,4,9\}
{
−
5
,
−
3
,
4
,
9
}
\newline
(B)
{
−
5
,
−
3
,
4
,
5
,
9
}
\{-5,-3,4,5,9\}
{
−
5
,
−
3
,
4
,
5
,
9
}
\newline
(C)
{
−
3
,
−
2
,
4
,
9
}
\{-3,-2,4,9\}
{
−
3
,
−
2
,
4
,
9
}
\newline
(D)
{
−
3
,
−
2
,
5
,
9
}
\{-3,-2,5,9\}
{
−
3
,
−
2
,
5
,
9
}
Get tutor help
Posted 9 months ago
Question
Every day at lunch, Vicky swims laps in the pool for one hour. The faster her speed, the more laps she is able to swim in the hour.
s
=
s =
s
=
the speed at which Vicky swims
l
=
l =
l
=
the number of laps Vicky is able to swim in one hour Which of the variables is independent and which is dependent?
\newline
Choices:
\newline
[
A
]
s
is the independent variable and
l
is the dependent variable
[A] s \text{ is the independent variable and } l \text{ is the dependent variable }
[
A
]
s
is the independent variable and
l
is the dependent variable
\newline
[
B
]
l
is the independent variable and
s
is the dependent variable
[B] l \text{ is the independent variable and } s \text{ is the dependent variable }
[
B
]
l
is the independent variable and
s
is the dependent variable
Get tutor help
Posted 9 months ago
Question
Use the following function rule to find
f
(
4
)
f(4)
f
(
4
)
.
\newline
f
(
x
)
=
9
−
x
f(x) = 9 - x
f
(
x
)
=
9
−
x
\newline
f
(
4
)
=
f(4) =
f
(
4
)
=
Get tutor help
Posted 1 year ago
Question
Simplify to create an equivalent expression.
\newline
−
2
(
−
5
n
+
6
)
+
5
(
2
−
7
n
)
-2(-5n+6)+5(2-7n)
−
2
(
−
5
n
+
6
)
+
5
(
2
−
7
n
)
\newline
Choose
1
1
1
answer:
\newline
(A)
−
2
-2
−
2
\newline
(B)
−
25
n
+
10
-25n+10
−
25
n
+
10
\newline
(C)
−
25
n
+
2
-25n+2
−
25
n
+
2
\newline
(D)
−
25
n
−
2
-25n-2
−
25
n
−
2
Get tutor help
Posted 9 months ago
Question
Simplify to create an equivalent expression.
\newline
3
n
+
2
(
−
2
n
−
1
)
3n+2(-2n-1)
3
n
+
2
(
−
2
n
−
1
)
\newline
Choose
1
1
1
answer:
\newline
(A)
−
n
+
2
-n+2
−
n
+
2
\newline
(B)
n
+
2
n+2
n
+
2
\newline
(C)
−
n
−
2
-n-2
−
n
−
2
\newline
(D)
n
−
2
n-2
n
−
2
Get tutor help
Posted 1 year ago
Question
Simplify to create an equivalent expression.
\newline
5
(
10
k
+
1
)
+
2
(
2
+
8
k
)
5(10k+1)+2(2+8k)
5
(
10
k
+
1
)
+
2
(
2
+
8
k
)
\newline
Choose
1
1
1
answer:
\newline
(A)
66
k
+
9
66k+9
66
k
+
9
\newline
(B)
64
k
+
9
64k+9
64
k
+
9
\newline
(C)
66
k
+
54
66k+54
66
k
+
54
\newline
(D)
64
k
−
9
64k-9
64
k
−
9
Get tutor help
Posted 1 year ago
Question
Simplify to create an equivalent expression.
\newline
5
+
7
(
8
r
−
2
)
5+7(8r-2)
5
+
7
(
8
r
−
2
)
\newline
Choose
1
1
1
answer:
\newline
(A)
56
r
+
3
56r+3
56
r
+
3
\newline
(B)
56
r
+
9
56r+9
56
r
+
9
\newline
(C)
8
r
−
9
8r-9
8
r
−
9
\newline
(D)
56
r
−
9
56r-9
56
r
−
9
Get tutor help
Posted 1 year ago
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