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Devin is a landscaper who needs to prepare different types of grass seed for his customers' yards. Bluegrass seed costs 
$2.00 per pound while drought-resistant seed costs 
$3.00 per pound. If for a particular day the two types of grass seed totaled 
$68.00 and together weighed 25 pounds, how many pounds of bluegrass seed did Devin prepare?
Choose 1 answer:
(A) 4
(B) 7
(c) 18
(D) 21

Devin is a landscaper who needs to prepare different types of grass seed for his customers' yards. Bluegrass seed costs $2.00 \$ 2.00 per pound while drought-resistant seed costs $3.00 \$ 3.00 per pound. If for a particular day the two types of grass seed totaled $68.00 \$ 68.00 and together weighed 2525 pounds, how many pounds of bluegrass seed did Devin prepare?\newlineChoose 11 answer:\newline(A) 44\newline(B) 77\newline(C) 1818\newline(D) 2121

Full solution

Q. Devin is a landscaper who needs to prepare different types of grass seed for his customers' yards. Bluegrass seed costs $2.00 \$ 2.00 per pound while drought-resistant seed costs $3.00 \$ 3.00 per pound. If for a particular day the two types of grass seed totaled $68.00 \$ 68.00 and together weighed 2525 pounds, how many pounds of bluegrass seed did Devin prepare?\newlineChoose 11 answer:\newline(A) 44\newline(B) 77\newline(C) 1818\newline(D) 2121
  1. Denoting the seeds: Let's denote the number of pounds of bluegrass seed as BB and the number of pounds of drought-resistant seed as DD. We have two types of information: the total cost and the total weight.
  2. Equation for total cost: The total cost of the seeds is $68.00\$68.00. Since bluegrass seed costs $2.00\$2.00 per pound and drought-resistant seed costs $3.00\$3.00 per pound, we can write the following equation for the total cost:\newline2B+3D=682B + 3D = 68
  3. Equation for total weight: The total weight of the seeds is 2525 pounds. This gives us another equation:\newlineB+D=25B + D = 25
  4. System of equations: We now have a system of two equations with two variables:\newline11) 2B+3D=682B + 3D = 68\newline22) B+D=25B + D = 25\newlineWe can solve this system using substitution or elimination. Let's use the substitution method. We can solve the second equation for DD:\newlineD=25BD = 25 - B
  5. Substitution method: Substitute D=25BD = 25 - B into the first equation:\newline2B+3(25B)=682B + 3(25 - B) = 68\newlineNow, distribute the 33:\newline2B+753B=682B + 75 - 3B = 68
  6. Substituting DD into the first equation: Combine like terms:\newline2B3B=68752B - 3B = 68 - 75\newlineB=7-B = -7
  7. Combining like terms: Multiply both sides by 1-1 to solve for BB:\newlineB=7B = 7
  8. Solving for B: So, Devin prepared 77 pounds of bluegrass seed.

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