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David is writing an explicit function for the arithmetic sequence:

10,13,16,19,dots
He comes up with 
s(n)=7+3n.
What domain should David use for 
s so it generates the sequence?
Choose 1 answer:
(A) 
n >= 0 where 
n is an integer
(B) 
n >= 0 where 
n is any number
(c) 
n >= 1 where 
n is an integer
(D) 
n >= 1 where 
n is any number

David is writing an explicit function for the arithmetic sequence:\newline10,13,16,19, 10,13,16,19, \ldots \newlineHe comes up with s(n)=7+3n s(n)=7+3 n .\newlineWhat domain should David use for s s so it generates the sequence?\newlineChoose 11 answer:\newline(A) n0 n \geq 0 where n n is an integer\newline(B) n0 n \geq 0 where n n is any number\newline(C) n1 n \geq 1 where n n is an integer\newline(D) n1 n \geq 1 where n n is any number

Full solution

Q. David is writing an explicit function for the arithmetic sequence:\newline10,13,16,19, 10,13,16,19, \ldots \newlineHe comes up with s(n)=7+3n s(n)=7+3 n .\newlineWhat domain should David use for s s so it generates the sequence?\newlineChoose 11 answer:\newline(A) n0 n \geq 0 where n n is an integer\newline(B) n0 n \geq 0 where n n is any number\newline(C) n1 n \geq 1 where n n is an integer\newline(D) n1 n \geq 1 where n n is any number
  1. Step 11: Checking first term: To determine the correct domain for the function s(n)s(n) that generates the given arithmetic sequence, we first need to check if the function correctly produces the terms of the sequence when we input the appropriate values of nn. The given sequence is 10,13,16,19,10, 13, 16, 19, \ldots and the function is s(n)=7+3ns(n) = 7 + 3n. Let's check the first term by substituting n=1n = 1 into the function.\newlines(1)=7+3(1)=7+3=10s(1) = 7 + 3(1) = 7 + 3 = 10
  2. Step 22: Checking second term: Now let's check the second term by substituting n=2 n = 2 into the function.s(2)=7+3(2)=7+6=13 s(2) = 7 + 3(2) = 7 + 6 = 13
  3. Step 33: Checking third term: Next, we check the third term by substituting n=3 n = 3 into the function.s(3)=7+3(3)=7+9=16 s(3) = 7 + 3(3) = 7 + 9 = 16
  4. Step 44: Checking fourth term: Finally, let's check the fourth term by substituting n=4 n = 4 into the function.s(4)=7+3(4)=7+12=19 s(4) = 7 + 3(4) = 7 + 12 = 19
  5. Step 55: Determining domain for s(n)s(n): Since the function s(n)=7+3ns(n) = 7 + 3n correctly produces the terms of the sequence when nn starts at 11 and increases by 11 for each subsequent term, we can conclude that the domain of nn should start at 11. Additionally, since the sequence is arithmetic and each term is determined by adding a constant difference to the previous term, nn should be an integer to ensure that we only generate the terms of the sequence and not any values in between.
  6. Step 66: Conclusion: Given the above reasoning, the correct domain for the function s(n)s(n) to generate the arithmetic sequence is "n1n \geq 1 where nn is an integer". This corresponds to option (C)(C).

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