Create a list of steps, in order, that will solve the following equation. 2(x+(3)/(4))^(2)-5=123 Solution steps: Add 2 to both sides Add 5 to both sides Divide both sides by 2 Multiply both sides by 2 Subtract 5 from both sides Subtract (3)/(4) from both sides

Isolate quadratic term: Add 5 to both sides of the equation to isolate the quadratic term. 2(x+(3/4))^2 - 5 + 5 = 123 + 5 2(x+(3/4))^2 = 128Solve for squared term: Divide both sides by 2 to solve for the squared term. 2(x+(3/4))^2 / 2 = 128 / 2 (x+(3/4))^2 = 64Solve for x + (3/4): Take the square root of both sides to solve for x + (3/4). √((x+(3/4))^2) = ±√64 x + (3/4) = ±8Solve for x: Subtract (3/4) from both sides to solve for x. x + (3/4) - (3/4) = ±8 - (3/4) x = ±8 - (3/4)Simplify solutions: Simplify the right side of the equation for both positive and negative solutions. For the positive solution: x = 8 - (3/4) x = 8 - 0.75 x = 7.25 For the negative solution: x = -8 - (3/4) x = -8 - 0.75 x = -8.75

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Create a list of steps, in order, that will solve the following equation.

2(x+(3)/(4))^(2)-5=123
Solution steps:
Add 2 to both sides
Add 5 to both sides
Divide both sides by 2
Multiply both sides by 2
Subtract 5 from both sides
Subtract
(3)/(4) from both sides

Create a list of steps, in order, that will solve the following equation. $\newline$ $2(x+\frac{3}{4})^{2}-5=123$ $\newline$ Solution steps: $\newline$ Add $2$ to both sides $\newline$ Add $5$ to both sides $\newline$ Divide both sides by $2$ $\newline$ Multiply both sides by $2$ $\newline$ Subtract $5$ from both sides $\newline$ Subtract $\newline$ $\frac{3}{4}$ from both sides

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Math Problems

Algebra 2

Solve a quadratic equation using square roots

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Q. Create a list of steps, in order, that will solve the following equation.

\newline

2(x+\frac{3}{4})^{2}-5=123

\newline

Solution steps:

\newline

Add

2

to both sides

\newline

Add

5

to both sides

\newline

Divide both sides by

2

\newline

Multiply both sides by

2

\newline

Subtract

5

from both sides

\newline

Subtract

\newline

\frac{3}{4}

from both sides

Isolate quadratic term: Add $5$ to both sides of the equation to isolate the quadratic term. $\newline$ $2(x+(\frac{3}{4}))^2 - 5 + 5 = 123 + 5$ $\newline$ $2(x+(\frac{3}{4}))^2 = 128$
Solve for squared term: Divide both sides by $2$ to solve for the squared term. $\frac{2(x+(\frac{3}{4}))^2}{2} = \frac{128}{2}$ $(x+(\frac{3}{4}))^2 = 64$
Solve for $x + \frac{3}{4}$ : Take the square root of both sides to solve for $x + \frac{3}{4}$ . $\newline$ $\sqrt{\left(x+\frac{3}{4}\right)^2} = \pm\sqrt{64}$ $\newline$ $x + \frac{3}{4} = \pm8$
Solve for x: Subtract $(\frac{3}{4})$ from both sides to solve for x. $\newline$ $x + \left(\frac{3}{4}\right) - \left(\frac{3}{4}\right) = \pm8 - \left(\frac{3}{4}\right)$ $\newline$ $x = \pm8 - \left(\frac{3}{4}\right)$
Simplify solutions: Simplify the right side of the equation for both positive and negative solutions. $\newline$ For the positive solution: $\newline$ $x = 8 - \frac{3}{4}$ $\newline$ $x = 8 - 0.75$ $\newline$ $x = 7.25$ $\newline$ For the negative solution: $\newline$ $x = -8 - \frac{3}{4}$ $\newline$ $x = -8 - 0.75$ $\newline$ $x = -8.75$