Complete the recursive formula of the geometric sequence 7,-14,28,-56,dots. a(1)= a(n)=a(n-1).

Identify first term: Identify the first term of the sequence. The first term of the sequence is given as 7.Determine common ratio: Determine the common ratio by dividing the second term by the first term. The common ratio (r) is -14 divided by 7, which equals -2.Write recursive formula: Write the recursive formula using the first term and the common ratio. The recursive formula for a geometric sequence is a(n) = a(n-1) * r. We have a(1) = 7 and r = -2.Substitute values into formula: Substitute the values into the recursive formula. The recursive formula is a(n) = a(n-1) * (-2), with a(1) = 7.

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Complete the recursive formula of the geometric sequence
7,-14,28,-56,dots.

a(1)=
a(n)=a(n-1).

Complete the recursive formula of the geometric sequence $\newline$ $7,-14,28,-56,\dots.$ $\newline$ $a(1)=$ $\newline$ $a(n)=a(n-1)\cdot.$

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Math Problems

Algebra 1

Write variable expressions for geometric sequences

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Q. Complete the recursive formula of the geometric sequence

\newline

7,-14,28,-56,\dots.

\newline

a(1)=

\newline

a(n)=a(n-1)\cdot.

Identify first term: Identify the first term of the sequence. $\newline$ The first term of the sequence is given as $7$ .
Determine common ratio: Determine the common ratio by dividing the second term by the first term. $\newline$ The common ratio $r$ is $-14$ divided by $7$ , which equals $-2$ .
Write recursive formula: Write the recursive formula using the first term and the common ratio. $\newline$ The recursive formula for a geometric sequence is $a(n) = a(n-1) \times r$ . We have $a(1) = 7$ and $r = -2$ .
Substitute values into formula: Substitute the values into the recursive formula. $\newline$ The recursive formula is $a(n) = a(n-1) \times (-2)$ , with $a(1) = 7$ .