Complete the recursive formula of the geometric sequence 56,-28,14,-7,dots. d(1)= d(n)=d(n-1).

Identifying the first term: We have the sequence: 56, -28, 14, -7, ... First, we identify the first term of the sequence. The first term is d(1) = 56.Finding the common ratio: Next, we need to find the common ratio (r) by dividing the second term by the first term. r = d(2) / d(1) = -28 / 56 = -1/2.Writing the recursive formula: Now, we can write the recursive formula for the sequence using the first term and the common ratio. The recursive formula is: d(1) = 56 d(n) = d(n-1) * r, where r = -1/2.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Complete the recursive formula of the geometric sequence
56,-28,14,-7,dots.

d(1)=
d(n)=d(n-1).

Complete the recursive formula of the geometric sequence $\newline$ $56,-28,14,-7,\dots$ . $\newline$ $d(1)=$ $\newline$ $d(n)=d(n-1)\cdot$

View step-by-step help

Home

Math Problems

Algebra 1

Write variable expressions for geometric sequences

Full solution

Q. Complete the recursive formula of the geometric sequence

\newline

56,-28,14,-7,\dots

\newline

d(1)=

\newline

d(n)=d(n-1)\cdot

Identifying the first term: We have the sequence: $56, -28, 14, -7, \ldots$ $\newline$ First, we identify the first term of the sequence. $\newline$ The first term is $d(1) = 56$ .
Finding the common ratio: Next, we need to find the common ratio $r$ by dividing the second term by the first term. $r = \frac{d(2)}{d(1)} = \frac{-28}{56} = -\frac{1}{2}.$
Writing the recursive formula: Now, we can write the recursive formula for the sequence using the first term and the common ratio. $\newline$ The recursive formula is: $\newline$ $d(1) = 56$ $\newline$ $d(n) = d(n-1) \times r$ , where $r = -\frac{1}{2}$ .