Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Complete the recursive formula of the geometric sequence 
500,200,80,32,dots.

c(1)= 
c(n)=c(n-1).

Complete the recursive formula of the geometric sequence \newline500,200,80,32,500, 200, 80, 32, \dots.\newlinec(1)=c(1)= \newlinec(n)=c(n1)c(n)=c(n-1)\cdot

Full solution

Q. Complete the recursive formula of the geometric sequence \newline500,200,80,32,500, 200, 80, 32, \dots.\newlinec(1)=c(1)= \newlinec(n)=c(n1)c(n)=c(n-1)\cdot
  1. Identify first term: We are given the sequence 500500, 200200, 8080, 3232, ...\newlineFirst, we identify the first term of the sequence.\newlineThe first term is 500500.
  2. Find common ratio: Next, we need to find the common ratio by dividing the second term by the first term.\newlineThe common ratio rr is 200500=0.4\frac{200}{500} = 0.4.
  3. Write recursive formula: Now we can write the recursive formula for the geometric sequence.\newlineThe first term is given by c(1)=500c(1) = 500.\newlineFor n > 1, the nnth term is found by multiplying the previous term by the common ratio.\newlineSo, c(n)=c(n1)×0.4c(n) = c(n-1) \times 0.4.

More problems from Write variable expressions for geometric sequences