Complete the recursive formula of the geometric sequence 10,6,3.6,2.16,dots. a(1)= a(n)=a(n-1).

Identify first term: We are given the sequence: 10, 6, 3.6, 2.16, ... First, we need to identify the first term of the sequence, which is given as 10. So, a(1) = 10.Find common ratio: Next, we need to find the common ratio by dividing the second term by the first term. The common ratio r = 6 / 10 = 0.6.Write recursive formula: Now, we can write the recursive formula for the sequence using the first term and the common ratio. The recursive formula is a(n) = a(n-1) * r, where r is the common ratio. Substituting the value of r, we get a(n) = a(n-1) * 0.6.

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Complete the recursive formula of the geometric sequence
10,6,3.6,2.16,dots.

a(1)=
a(n)=a(n-1).

Complete the recursive formula of the geometric sequence $\newline$ $10, 6, 3.6, 2.16, \dots$ . $\newline$ $a(1)=$ $\newline$ $a(n)=a(n-1)\cdot$

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Algebra 1

Write variable expressions for geometric sequences

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Q. Complete the recursive formula of the geometric sequence

\newline

10, 6, 3.6, 2.16, \dots

\newline

a(1)=

\newline

a(n)=a(n-1)\cdot

Identify first term: We are given the sequence: $10$ , $6$ , $3.6$ , $2.16$ , ... $\newline$ First, we need to identify the first term of the sequence, which is given as $10$ . $\newline$ So, $a(1) = 10$ .
Find common ratio: Next, we need to find the common ratio by dividing the second term by the first term. $\newline$ The common ratio $r = \frac{6}{10} = 0.6$ .
Write recursive formula: Now, we can write the recursive formula for the sequence using the first term and the common ratio. $\newline$ The recursive formula is $a(n) = a(n-1) \times r$ , where $r$ is the common ratio. $\newline$ Substituting the value of $r$ , we get $a(n) = a(n-1) \times 0.6$ .