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Complete the recursive formula of the arithmetic sequence

8,-5,-18,-31,dots

d(1)=

d(n)=d(n-1)+

Complete the recursive formula of the arithmetic sequence\newline8,5,18,31, 8,-5,-18,-31, \ldots \text {. } \newlined(1)= d(1)= \newlined(n)=d(n1)+ d(n)=d(n-1)+

Full solution

Q. Complete the recursive formula of the arithmetic sequence\newline8,5,18,31, 8,-5,-18,-31, \ldots \text {. } \newlined(1)= d(1)= \newlined(n)=d(n1)+ d(n)=d(n-1)+
  1. Determining the Common Difference: To find the recursive formula for the arithmetic sequence, we need to determine the common difference between consecutive terms. We can do this by subtracting any term from the term that follows it.\newlineCalculation: \newline58=13-5 - 8 = -13\newline18(5)=18+5=13-18 - (-5) = -18 + 5 = -13\newline31(18)=31+18=13-31 - (-18) = -31 + 18 = -13\newlineThe common difference dd is 13-13.
  2. Writing the Recursive Formula: Now that we have the common difference, we can write the recursive formula. The recursive formula for an arithmetic sequence is given by:\newlined(n) = d(n1-1) + d, where d(n) is the nnth term and dd is the common difference.\newlineSince the first term d(1)d(1) is 88, we can write the recursive formula as:\newlined(1)=8d(1) = 8\newlined(n)=d(n1)13d(n) = d(n-1) - 13 (since the common difference is 13-13)

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