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Complete the recursive formula of the arithmetic sequence

{:[-5","-25","-45","-65","dots.],[b(1)=],[b(n)=b(n-1)+◻]:}

Complete the recursive formula of the arithmetic sequence\newline5,25,45,65,.b(1)=b(n)=b(n1)+ \begin{array}{l} -5,-25,-45,-65, \ldots . \\ b(1)=\square \\ b(n)=b(n-1)+\square \end{array}

Full solution

Q. Complete the recursive formula of the arithmetic sequence\newline5,25,45,65,.b(1)=b(n)=b(n1)+ \begin{array}{l} -5,-25,-45,-65, \ldots . \\ b(1)=\square \\ b(n)=b(n-1)+\square \end{array}
  1. Identify first term: Identify the first term of the sequence. The first term, b(1)b(1), is given as 5-5. This will be the starting point of our recursive formula.
  2. Determine common difference: Determine the common difference by subtracting any term from the term that follows it. For instance, subtracting the first term from the second term: 25(5)=20-25 - (-5) = -20. This is the common difference, which is consistent throughout the sequence.
  3. Write recursive formula: Write the recursive formula using the first term and the common difference. The recursive formula for an arithmetic sequence is b(n)=b(n1)+db(n) = b(n-1) + d, where dd is the common difference. Since we have determined that the common difference is 20-20, we can write the recursive formula as b(n)=b(n1)20b(n) = b(n-1) - 20.

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