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Complete the recursive formula of the arithmetic sequence

{:[-3","-1","1","3","dots],[b(1)=◻],[b(n)=b(n-1)+]:}

Complete the recursive formula of the arithmetic sequence\newline3,1,1,3,b(1)=b(n)=b(n1)+ \begin{array}{l} -3,-1,1,3, \ldots \\ b(1)=\square \\ b(n)=b(n-1)+ \end{array}

Full solution

Q. Complete the recursive formula of the arithmetic sequence\newline3,1,1,3,b(1)=b(n)=b(n1)+ \begin{array}{l} -3,-1,1,3, \ldots \\ b(1)=\square \\ b(n)=b(n-1)+ \end{array}
  1. Identify first term: Identify the first term of the sequence. The first term is given as 3-3.
  2. Determine common difference: Determine the common difference by subtracting the first term from the second term. The second term is 1-1, so the common difference is 1(3)=2-1 - (-3) = 2.
  3. Write recursive formula: Write the recursive formula using the first term and the common difference. The recursive formula for an arithmetic sequence is b(n)=b(n1)+db(n) = b(n-1) + d, where dd is the common difference.
  4. Substitute common difference: Substitute the common difference into the recursive formula. Since the common difference is 22, the recursive formula becomes b(n)=b(n1)+2b(n) = b(n-1) + 2.
  5. Include initial condition: Include the initial condition that defines the first term of the sequence. The initial condition is b(1)=3b(1) = -3.

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