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Complete the recursive formula of the arithmetic sequence

{:[-17","-8","1","10","dots.],[a(1)=],[a(n)=a(n-1)+]:}

Complete the recursive formula of the arithmetic sequence\newline17,8,1,10,.a(1)=a(n)=a(n1)+ \begin{array}{l} -17,-8,1,10, \ldots . \\ a(1)= \\ a(n)=a(n-1)+ \end{array}

Full solution

Q. Complete the recursive formula of the arithmetic sequence\newline17,8,1,10,.a(1)=a(n)=a(n1)+ \begin{array}{l} -17,-8,1,10, \ldots . \\ a(1)= \\ a(n)=a(n-1)+ \end{array}
  1. Identify common difference: Identify the common difference in the sequence by subtracting any term from the term that follows it. For instance, subtract 17-17 from 8-8 to find the common difference.\newlineCalculation: 8(17)=8+17=9-8 - (-17) = -8 + 17 = 9.
  2. Confirm common difference: Confirm the common difference by checking if it is consistent between other consecutive terms. For example, subtract 8-8 from 11 to see if the common difference is still 99.\newlineCalculation: 1(8)=1+8=91 - (-8) = 1 + 8 = 9.
  3. Write recursive formula: Write the recursive formula for the arithmetic sequence using the first term and the common difference. The recursive formula has the form a(n)=a(n1)+da(n) = a(n-1) + d, where dd is the common difference.\newlineSince the first term a(1)a(1) is given as 17-17 and the common difference dd is 99, the recursive formula is a(n)=a(n1)+9a(n) = a(n-1) + 9.

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