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Complete the recursive formula of the arithmetic sequence

{:[-16","-33","-50","-67","dots],[c(1)=],[c(n)=c(n-1)+◻]:}

Complete the recursive formula of the arithmetic sequence\newline16,33,50,67,.c(1)=c(n)=c(n1)+ \begin{array}{l} -16,-33,-50,-67, \ldots . \\ c(1)= \\ c(n)=c(n-1)+\square \end{array}

Full solution

Q. Complete the recursive formula of the arithmetic sequence\newline16,33,50,67,.c(1)=c(n)=c(n1)+ \begin{array}{l} -16,-33,-50,-67, \ldots . \\ c(1)= \\ c(n)=c(n-1)+\square \end{array}
  1. Identify the pattern: Identify the pattern in the sequence to determine the common difference. The sequence is 16-16, 33-33, 50-50, 67-67, .... To find the common difference, subtract the first term from the second term: 33(16)=33+16=17-33 - (-16) = -33 + 16 = -17.
  2. Verify the common difference: Verify the common difference by subtracting the second term from the third term: 50(33)=50+33=17-50 - (-33) = -50 + 33 = -17. The common difference is consistent, confirming that the sequence is arithmetic with a common difference of 17-17.
  3. Write the recursive formula: Write the recursive formula for the arithmetic sequence. The recursive formula has the form c(n)=c(n1)+dc(n) = c(n-1) + d, where dd is the common difference. Since we have determined that the common difference is 17-17, the recursive formula is c(n)=c(n1)17c(n) = c(n-1) - 17.
  4. State the initial term: State the initial term of the sequence in the recursive formula. The first term, c(1)c(1), is given as 16-16. Therefore, the complete recursive formula is:\newlinec(1)=16,c(1) = -16,\newlinec(n) = c(n-1) - 17 \text{ for } n > 1.

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