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Complete the recursive formula of the arithmetic sequence

{:[-15","-11","-7","-3","dots.],[c(1)=],[c(n)=c(n-1)+◻]:}

Complete the recursive formula of the arithmetic sequence\newline15,11,7,3,.c(1)=c(n)=c(n1)+ \begin{array}{l} -15,-11,-7,-3, \ldots . \\ c(1)=\square \\ c(n)=c(n-1)+\square \end{array}

Full solution

Q. Complete the recursive formula of the arithmetic sequence\newline15,11,7,3,.c(1)=c(n)=c(n1)+ \begin{array}{l} -15,-11,-7,-3, \ldots . \\ c(1)=\square \\ c(n)=c(n-1)+\square \end{array}
  1. Identify common difference: Identify the common difference in the sequence by subtracting any term from the term that follows it. The sequence is 15-15, 11-11, 7-7, 3-3, ... Subtracting a term from the next term: 11(15)=11+15=4-11 - (-15) = -11 + 15 = 4. The common difference, dd, is 44.
  2. Write recursive formula: Write the recursive formula using the common difference. The recursive formula for an arithmetic sequence is given by c(n)=c(n1)+dc(n) = c(n-1) + d, where c(n)c(n) is the nth term, c(n1)c(n-1) is the previous term, and dd is the common difference. Since we have found that d=4d = 4, we can write the recursive formula as c(n)=c(n1)+4c(n) = c(n-1) + 4.
  3. Determine first term: Determine the first term of the sequence to complete the recursive formula. The first term, c(1)c(1), is given as 15-15. So, we include this in our recursive formula.

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