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Complete the recursive formula of the arithmetic sequence 
14,30,46,62,dots..

{:[d(1)=◻],[d(n)=d(n-1)+]:}

Complete the recursive formula of the arithmetic sequence\newline14,30,46,62,..  14,30,46,62, \ldots \text {.. } \newlined(1)=d(n)=d(n1)+ \begin{array}{l} d(1)=\square \\ d(n)=d(n-1)+ \end{array}

Full solution

Q. Complete the recursive formula of the arithmetic sequence\newline14,30,46,62,..  14,30,46,62, \ldots \text {.. } \newlined(1)=d(n)=d(n1)+ \begin{array}{l} d(1)=\square \\ d(n)=d(n-1)+ \end{array}
  1. Identify first term: Identify the first term of the sequence. The first term is given as 1414.
  2. Determine common difference: Determine the common difference by subtracting the first term from the second term. The second term is 3030, so the common difference is 3014=1630 - 14 = 16.
  3. Write recursive formula: Write the recursive formula using the first term and the common difference. The recursive formula for an arithmetic sequence is given by:\newlined(11) = first term,\newlined(n) = d(n1-1) + common difference, for n > 11.\newlineSubstitute the first term and the common difference into the formula.

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