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Complete the recursive formula of the arithmetic sequence

{:[13","6","-1","-8","dots],[c(1)=◻],[c(n)=c(n-1)+]:}

Complete the recursive formula of the arithmetic sequence\newline13,6,1,8, 13,6,-1,-8, \ldots \text {. } \newlinec(1)= c(1)= \newlinec(n)=c(n1)+ c(n)=c(n-1)+

Full solution

Q. Complete the recursive formula of the arithmetic sequence\newline13,6,1,8, 13,6,-1,-8, \ldots \text {. } \newlinec(1)= c(1)= \newlinec(n)=c(n1)+ c(n)=c(n-1)+
  1. Identify common difference: Identify the common difference in the sequence by subtracting any term from the term that follows it. The sequence is 13,6,1,8,extellipsis13, 6, -1, -8, extellipsis Subtract the second term from the first term to find the common difference: 613=76 - 13 = -7.
  2. Verify common difference: Verify the common difference by subtracting another pair of consecutive terms to ensure consistency. Subtract the fourth term from the third term: 8(1)=7-8 - (-1) = -7. The common difference is consistent, so it is 7-7.
  3. Write recursive formula: Write the recursive formula for the arithmetic sequence using the common difference. The recursive formula has the form c(n)=c(n1)+dc(n) = c(n-1) + d, where dd is the common difference. Since we have found that d=7d = -7, the recursive formula is c(n)=c(n1)7c(n) = c(n-1) - 7.
  4. State initial term: State the initial term of the sequence in the recursive formula. The first term of the sequence, c(1)c(1), is given as 1313. So the complete recursive formula is c(1)=13c(1) = 13, c(n)=c(n1)7c(n) = c(n-1) - 7 for n > 1.

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