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Complete the recursive formula of the arithmetic sequence

{:[-1","-13","-25","-37","dots.],[a(1)=◻],[a(n)=a(n-1)+◻]:}

Complete the recursive formula of the arithmetic sequence\newline1,13,25,37,.a(1)=a(n)=a(n1)+ \begin{array}{l} -1,-13,-25,-37, \ldots . \\ a(1)=\square \\ a(n)=a(n-1)+\square \end{array}

Full solution

Q. Complete the recursive formula of the arithmetic sequence\newline1,13,25,37,.a(1)=a(n)=a(n1)+ \begin{array}{l} -1,-13,-25,-37, \ldots . \\ a(1)=\square \\ a(n)=a(n-1)+\square \end{array}
  1. Identify first term: Identify the first term of the sequence. The first term of the sequence is given as 1-1. This will be our a(1)a(1) in the recursive formula.
  2. Determine common difference: Determine the common difference between consecutive terms. To find the common difference, subtract the first term from the second term: 13(1)=12-13 - (-1) = -12. This is the common difference dd for the arithmetic sequence.
  3. Write recursive formula: Write the recursive formula using the first term and the common difference. The recursive formula for an arithmetic sequence is a(n)=a(n1)+da(n) = a(n-1) + d. Since we have a(1)=1a(1) = -1 and d=12d = -12, the recursive formula becomes a(n)=a(n1)12a(n) = a(n-1) - 12.
  4. Check formula with given terms: Check the recursive formula with the given terms to ensure it is correct. If we apply the formula a(n)=a(n1)12a(n) = a(n-1) - 12 starting from the first term, we should get the subsequent terms of the sequence. For example, a(2)a(2) should be a(1)12a(1) - 12, which is 112=13-1 - 12 = -13. This matches the second term of the sequence, so the formula appears to be correct.

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