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Complete the recursive formula of the arithmetic sequence

{:[0","11","22","33","dots.],[c(1)=◻],[c(n)=c(n-1)+]:}

Complete the recursive formula of the arithmetic sequence 0,11,22,33, 0,11,22,33, \ldots ..\newlinec(1)= c(1)= \newlinec(n)=c(n1)+ c(n)=c(n-1)+

Full solution

Q. Complete the recursive formula of the arithmetic sequence 0,11,22,33, 0,11,22,33, \ldots ..\newlinec(1)= c(1)= \newlinec(n)=c(n1)+ c(n)=c(n-1)+
  1. Identify first term and common difference: Identify the first term of the sequence and the common difference between consecutive terms. The first term is 00, and by observing the sequence, we can see that each term increases by 1111 from the previous term. Therefore, the common difference is 1111.
  2. Write initial condition: Write the initial condition for the recursive formula. The initial condition specifies the first term of the sequence, which is 00. So, we have c(1)=0c(1) = 0.
  3. Determine recursive part: Determine the recursive part of the formula. Since the common difference is 1111, the recursive part of the formula will add 1111 to the previous term. This can be written as c(n)=c(n1)+11c(n) = c(n-1) + 11 for n > 1.
  4. Combine initial condition and recursive part: Combine the initial condition and the recursive part to write the complete recursive formula for the sequence. The complete recursive formula is:\newlinec(1)=0c(1) = 0,\newlinec(n)=c(n1)+11c(n) = c(n-1) + 11 for n > 1.

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