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Combine like terms to create an equivalent expression.
Enter any coefficients as simplified proper or improper fractions or integers.

-(6)/(5)-(2)/(3)v+(4)/(15)+(1)/(3)v

Combine like terms to create an equivalent expression.\newlineEnter any coefficients as simplified proper or improper fractions or integers.\newline6523v+415+13v-\frac{6}{5}-\frac{2}{3}v+\frac{4}{15}+\frac{1}{3}v

Full solution

Q. Combine like terms to create an equivalent expression.\newlineEnter any coefficients as simplified proper or improper fractions or integers.\newline6523v+415+13v-\frac{6}{5}-\frac{2}{3}v+\frac{4}{15}+\frac{1}{3}v
  1. Identify like terms: Identify like terms in the expression.\newlineThe expression given is 65-\frac{6}{5} - 23v\frac{2}{3}v + 415\frac{4}{15} + 13v\frac{1}{3}v. We need to combine like terms, which are terms that have the same variable part. In this case, the like terms are 23v-\frac{2}{3}v and 13v\frac{1}{3}v, which both have the variable 'v'. The other terms 65-\frac{6}{5} and 415\frac{4}{15} are constants and can be combined separately.
  2. Combine constant terms: Combine the constant terms.\newlineTo combine the constants 65-\frac{6}{5} and 415\frac{4}{15}, we need a common denominator. The least common denominator for 55 and 1515 is 1515. We convert 65-\frac{6}{5} to 1815-\frac{18}{15} so that both fractions have the same denominator.\newlineNow we can combine the constants: 1815+415=18+415=1415-\frac{18}{15} + \frac{4}{15} = \frac{-18 + 4}{15} = -\frac{14}{15}.
  3. Combine variable terms: Combine the variable terms.\newlineNow we combine the variable terms 23v-\frac{2}{3}v and 13v\frac{1}{3}v. Since they have the same variable part, we can simply add their coefficients: 23+13=2+13=13-\frac{2}{3} + \frac{1}{3} = \frac{-2 + 1}{3} = -\frac{1}{3}.\newlineSo the combined variable term is 13v-\frac{1}{3}v.
  4. Write final simplified expression: Write the final simplified expression.\newlineWe now have the combined constant term and the combined variable term. The final simplified expression is 1415(13)v-\frac{14}{15} - \left(\frac{1}{3}\right)v.

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